91. Decode Ways

2018/05/18 leetcode 共 800 字,约 3 分钟

Title

the problem link

A message containing letters from A-Z is being encoded to numbers using the following mapping: ‘A’ -> 1 ‘B’ -> 2 … ‘Z’ -> 26 Given a non-empty string containing only digits, determine the total number of ways to decode it.

Example 1:

Input: “12”

Output: 2

Explanation: It could be decoded as “AB” (1 2) or “L” (12).

Example 2:

Input: “226”

Output: 3

Explanation: It could be decoded as “BZ” (2 26), “VF” (22 6), or “BBF” (2 2 6).

Solution

动态规划

容易错误的测试用例有1,01,101

//cpp:
class Solution {
public:
	int numDecodings(string s) {
		if (s.length() == 0) return 0;
		vector<int> dp(s.length()+2);
		dp[s.length() - 1] = s[s.length() - 1] == '0' ? 0 : 1;
		dp[s.length()] = 1;
		for (int i = s.length() - 2; i >= 0; i--) {
			dp[i] = dp[i + 1];

			if (s[i] == '0') {
				dp[i] = 0;
				continue;
			}

			if (stoi(s.substr(i, 2)) <= 26) {
				dp[i] += dp[i + 2];
			}
			cout << dp[i] << endl;
		}
		return dp[0];
	}
};

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