Title
Given a singly linked list, determine if it is a palindrome.
Follow up: Could you do it in O(n) time and O(1) space?
反转链表,优化不够,只是反转后对比
Solution
//cpp:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* Reverse(ListNode* head){
ListNode *p1=NULL;
while(head){
ListNode *p=new ListNode(head->val);
p->next=p1;
p1=p;
head=head->next;
}
return p1;
}
bool isPalindrome(ListNode* head) {
ListNode* root=head;
ListNode* root1=Reverse(head);
while(root1&&root&&root1->val==root->val){
root1=root1->next;
root=root->next;
}
if(!root1&&!root){
return true;
}else{
return false;
}
}
};